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matlab tenth homework matlab tenth homework
习题6 这道题让我们求解整个系统的平衡位置,也就是求解使系统势能PE达到最小时的位置坐标,可以用fminunc来求解 P = [1100; 1800; 3300]; k1 = 4500;k2 = 1650;k3 = 1100; k4
2018-01-20
振动练习 振动练习
练习13一根均质、等截面杆,左端固定,右端自由。一附加质量(视为质点)位于距左端\(s\)处,\(M=\rho AL \)。绘制系统前四阶固有频率随\(s\)变化的曲线。 可以列出此杆的振动方程:$$\frac{\partial^
2017-12-21
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习题3 画出常态模型开环阶跃响应G_0 = tf([1],[1,1]); G_1 = tf([3.7],[0.75,0.6]); G_2 = tf([1.63],[0.94,0.92]); G_3 = tf([0.7,7,17],[
2017-12-19
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习题6Consider the free oscillation response(自由振动响应) data given in Table 9.7.Curve fit these data by assuming that the r
2017-12-07
matlab 单词本 matlab 单词本
word meaning undamped 不衰减的 angular coordinate 角坐标 pendulum 摆动 spring 弹簧 damper 阻尼器 excitation 激励 proto
2017-12-06
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习题8.1a% 很明显题目是个泊松分布,均值lambda=5 % i p_8 = poisspdf(8,5) fprintf('the probability of 8 calls per minute is %f',[p_8]) %
2017-11-29
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matlab工程分析第六次作业 习题6.1% Archimedean spiral phi = linspace(0, 6*pi, 200); x = phi.*cos(phi); y = phi.*sin(phi); plot(x,
2017-11-15
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matlab工程分析第四次和第五次作业 习题5.1% 5.1 clear all clc D_d = [6.00,3.00,2.00,1.50,1.20,1.10,1.07,1.05,1.03,1.01]; c = [0.88,0.8
2017-10-30
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matlab工程分析第三次作业 % 3.5 n = 0:1:15; Fn = 1/sqrt(5)*(((1+sqrt(5))/2).^n-((1-sqrt(5))/2).^n); fprintf(1,'F%2.0f= %.0f\n'
2017-10-13
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matlab工程分析第二次作业 % 2.3 %a y = [0,-0.2,0.4,-0.6,0.8,-1.0,-1.2,-1.4,1.6]; z = sin(y); nz = z(find(z<0)); min_nz = min(
2017-10-02
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matlab工程分析第一次作业 % 1.1 1^3+5^3+3^3 == 153 1^4+6^4+3^4+4^4 == 1634 5^6+4^6+8^6+8^6+3^6+4^6 == 548834 factorial(1)+factori
2017-10-02
matlab之初体验 matlab之初体验
matlab第一章 a=3 a = 3complex(3,4) ans = 3.0000 + 4.0000i%Example 1.1 x=0.1; a=0.5; y=sqrt(abs(exp(-pi*x)-sin(x)
2017-09-22